2 NaI (aq) + Na2SO4 (aq) + H2O (l) → Na2SO3 (aq) + I2 (s) + 2 NaOH (aq)
This is an oxidation-reduction (redox) reaction:
SVI + 2 e- → SIV (reduction)
2 I-I - 2 e- → 2 I0 (oxidation)
Na2SO4 is an oxidizing agent, NaI is a reducing agent.
This is an oxidation-reduction (redox) reaction:
SVI + 2 e- → SIV (reduction)
2 I-I - 2 e- → 2 I0 (oxidation)
Na2SO4 is an oxidizing agent, NaI is a reducing agent.
Reactants:
Products: