2 NaI (aq) + Br2 (aq) → 2 NaBr (aq) + I2 (s)
This is an oxidation-reduction (redox) reaction:
2 Br0 + 2 e- → 2 Br-I (reduction)
2 I-I - 2 e- → 2 I0 (oxidation)
Br2 is an oxidizing agent, NaI is a reducing agent.
This is a precipitation reaction: I2 is the formed precipitate.
Reactants:
- NaI
- Br2
Products: