4 NaBr + 2 NaBrO3 + 6 H2SO4 → 3 Br2 + 6 NaSO4 + 6 H2O
This is an oxidation-reduction (redox) reaction:
4 Br-I - 4 e- → 4 Br0 (oxidation)
2 BrV + 10 e- → 2 Br0 (reduction)
6 SVI - 6 e- → 6 SVII (oxidation)
NaBr is a reducing agent, NaBrO3 is an oxidizing agent, H2SO4 is a reducing agent.
Warning: Unknown compound 'NaSO4'