6 Na2S2O3 + 2 I3 → 3 Na2S4O6 + 6 NaI
This is an oxidation-reduction (redox) reaction:
12 SII - 6 e- → 12 S5/2 (oxidation)
6 I0 + 6 e- → 6 I-I (reduction)
Na2S2O3 is a reducing agent, I3 is an oxidizing agent.
Reactants:
- Na2S2O3
- I3
Products:
Warning: Unknown compound 'I3'