2 KMnO4 (aq) + 3 MnSO4 (aq) + 4 KOH (aq) → 2 H2O (l) + 3 K2SO4 (aq) + 5 MnO2 (s)
This is an oxidation-reduction (redox) reaction:
3 MnII - 6 e- → 3 MnIV (oxidation)
2 MnVII + 6 e- → 2 MnIV (reduction)
MnSO4 is a reducing agent, KMnO4 is an oxidizing agent (synproportionation (comproportionation)).
This is a precipitation reaction: MnO2 is the formed precipitate.