2 KMnO4 (aq) + 3 MnCl2 (aq) + 4 KOH (aq) → 5 MnO2 (s) + 6 KCl (aq) + 2 H2O (l)
This is an oxidation-reduction (redox) reaction:
3 MnII - 6 e- → 3 MnIV (oxidation)
2 MnVII + 6 e- → 2 MnIV (reduction)
MnCl2 is a reducing agent, KMnO4 is an oxidizing agent (synproportionation (comproportionation)).
This is a precipitation reaction: MnO2 is the formed precipitate.