10 KBr (aq) + 2 KIO3 (aq) + 6 H2SO4 (aq) → 5 Br2 (aq) + I2 (s) + 6 K2SO4 (aq) + 6 H2O (l)
This is an oxidation-reduction (redox) reaction:
10 Br-I - 10 e- → 10 Br0 (oxidation)
2 IV + 10 e- → 2 I0 (reduction)
KBr is a reducing agent, KIO3 is an oxidizing agent.
This is a precipitation reaction: I2 is the formed precipitate.