K2Cr2O7 + 14 HBr → 3 Br2 + 2 CrBr3 + 2 KBr + 7 H2O
This is an oxidation-reduction (redox) reaction:
6 Br-I - 6 e- → 6 Br0 (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
HBr is a reducing agent, K2Cr2O7 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
6 Br-I - 6 e- → 6 Br0 (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
HBr is a reducing agent, K2Cr2O7 is an oxidizing agent.
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