12 (I)- + 2 IO3 + 12 H+ → 7 I2 + 6 H2O
This is an oxidation-reduction (redox) reaction:
12 I-I - 12 e- → 12 I0 (oxidation)
2 IVI + 12 e- → 2 I0 (reduction)
I- is a reducing agent, IO3 is an oxidizing agent (synproportionation (comproportionation)).
Warning: Unknown compound 'IO3'