2 H2O + 7 O2 + 2 Na2 → 4 HNaO4
This is an oxidation-reduction (redox) reaction:
4 Na0 - 4 e- → 4 NaI (oxidation)
14 O0 + 7 e- → 14 O-1/2 (reduction)
2 O-II - 3 e- → 2 O-1/2 (oxidation)
Na2 is a reducing agent, O2 is an oxidizing agent, H2O is a reducing agent.
Warning: Unknown compound 'Na2'