3 C3H7OH + 2 K2Cr2O7 + 8 H2SO4 → 3 C3H6O2 + 2 Cr2(SO4)3 + 2 K2SO4 + 11 H2O
This is an oxidation-reduction (redox) reaction:
9 C-II - 12 e- → 9 C-2/3 (oxidation)
4 CrVI + 12 e- → 4 CrIII (reduction)
C3H7OH is a reducing agent, K2Cr2O7 is an oxidizing agent.
Reactants:
- C3H7OH – Propan-1-ol
- Other names: 1-Propanol , N , -Propyl alcohol|n-Propanol|n-PrOH|Ethylcarbinol|1-Hydroxypropane|Propionic alcohol|Propionyl alcohol|Propionylol|Propyl alcohol|Propylic alcohol|Propylol}}
- Appearance: Colorless liquid ; Clear colourless liquid with characteristic odour ; Colorless liquid with a mild, alcohol-like odor.
- K2Cr2O7 – Potassium dichromate(VI)
- H2SO4 – Sulfuric acid
Products: