6 Br2 + 6 Ba(OH)2 → Ba(BrO3)2 + 5 BaBr2 + 6 H2O
This is an oxidation-reduction (redox) reaction:
10 Br0 + 10 e- → 10 Br-I (reduction)
2 Br0 - 10 e- → 2 BrV (oxidation)
Br2 is both an oxidizing and a reducing agent (disproportionation (dismutation)).
Reactants:
- Br2
- Ba(OH)2
Products: