Bi(OH)3 + 3 Na(Sn(OH)3) + 3 NaOH → 3 Na2(Sn(OH)5) + Bi
This is an oxidation-reduction (redox) reaction:
BiIII + 3 e- → Bi0 (reduction)
3 SnII - 3 e- → 3 SnIII (oxidation)
Bi(OH)3 is an oxidizing agent, Na(Sn(OH)3) is a reducing agent.
This is an oxidation-reduction (redox) reaction:
BiIII + 3 e- → Bi0 (reduction)
3 SnII - 3 e- → 3 SnIII (oxidation)
Bi(OH)3 is an oxidizing agent, Na(Sn(OH)3) is a reducing agent.
Reactants:
Products: